Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is the distance from B to B′ ?
help?
@sleepyhead314 hey can you help with this?
\[distance formula: \sqrt{(x _{2}-x _{1})^{2} + (y _{2}-y _{1})^{2}} \]
can one of you please help me with this?
is there a diagram?
no :/
ok then, since there is no diagram, i will assume that the transformation is a translation. As such, the distance between A and A' will be the same as the distance between B and B', therefore simply find the distance between A and A' using the distance formula and u will have the answer. If you need help with using that formula, let me know.
need help
We need a point B to be able to calculate B'
not if its a translation only
and since no other information is provided in the question, then it is implied that it must be a translation
Where is point B? You need that to translate it to B' and find that point.
your answer is 5
plug everything into the distance formula and the output is 5
thank you
and no, you dont need to translate B to B', because a translation of the entire figure moves all point by the same distance
Oh nevermind. lol I misread the question. *facepalm*
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