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Chemistry 12 Online
OpenStudy (anonymous):

What is the number of nitrogen atoms in 60.0g of CO(NH2)2. (RAM: H,1;C,12;N,14;O,16;Avogadro constant:6x10^23) A 3X10^23 B 6x10^23 C 1.2x10^24 D 2.4x10^24 @Callisto

OpenStudy (anonymous):

@dan815

OpenStudy (somy):

find mole mole = mass / molecular mass u have mass & molecular mass u can get using periodic table

OpenStudy (somy):

once u find mole multiply it by Avogadro's number

OpenStudy (somy):

& u'll get the answer

OpenStudy (anonymous):

my answer is C. @Somy

OpenStudy (aaronandyson):

You had asked this question 14 days back http://openstudy.com/study#/updates/54f2a546e4b006da7538b11c

OpenStudy (anonymous):

But the answer is wrong :(

OpenStudy (somy):

ah wait we are not done sorry i didnt notice the N part

OpenStudy (somy):

so you find the total mole and of that total mole you have to find mole of N

OpenStudy (somy):

show me your first part working mole finding with the answer

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

\[CO(NH _{2})_{2}=60gmol^{-1}\]

OpenStudy (anonymous):

\[\frac{ 60g }{ 60gmol^{-1} }=1mol\]

OpenStudy (somy):

good now look 1 mole = whole compound molecular mass X mole = molecular mass of nitrogen

OpenStudy (somy):

X mole = 1 mole x molecular mass of nitrogen / molecular mass of the whole compound

OpenStudy (somy):

show me your next working using this

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

\[1mol~\times2\times6\times10^{23}mol^{-1}=12\times10^{23}\]

OpenStudy (anonymous):

\[=1.2\times10^{24}\]

OpenStudy (somy):

no no, this current working good now look 1 mole = whole compound molecular mass X mole = molecular mass of nitrogen X mole = 1 mole x molecular mass of nitrogen / molecular mass of the whole compound

OpenStudy (anonymous):

\[=\frac{ 1mol~\times28gmol^{-1} }{ 60gmol^{-1} }\]

OpenStudy (somy):

yep

OpenStudy (anonymous):

\[=0.5mol\]

OpenStudy (somy):

now multiply by Avogadro constant

OpenStudy (anonymous):

\[=0.5mol~\times6\times10^{23}\]

OpenStudy (somy):

yep

OpenStudy (anonymous):

\[=3\times10^{23}\]

OpenStudy (somy):

yas! :3 i hope its correct?

OpenStudy (somy):

coz if not than i'll be shocked lol

OpenStudy (anonymous):

Answer in the book say it is C.

OpenStudy (somy):

but C will be all atoms

OpenStudy (somy):

while q is asking for N atoms only

OpenStudy (somy):

i'll look through it again

OpenStudy (anonymous):

ok

OpenStudy (somy):

hmm you multiplied mole of the whole compound which was 1 mole by 2 did u do it because there are two N atoms in a compound?

OpenStudy (anonymous):

yep

OpenStudy (somy):

got it sorry thats my error http://prntscr.com/6h2t1n (different q but you can get whats going on)

OpenStudy (somy):

there are 2 N atoms per molecule of CO(NH2)2

OpenStudy (somy):

so we have to multiply by 2

OpenStudy (somy):

u are correct :) sorry had some errors in memory :D

OpenStudy (anonymous):

Thnx a lot @somy :)

OpenStudy (somy):

lol more like, thank you for refreshing my memory :)

OpenStudy (anonymous):

=]

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