What is the number of nitrogen atoms in 60.0g of CO(NH2)2. (RAM: H,1;C,12;N,14;O,16;Avogadro constant:6x10^23) A 3X10^23 B 6x10^23 C 1.2x10^24 D 2.4x10^24 @Callisto
@dan815
find mole mole = mass / molecular mass u have mass & molecular mass u can get using periodic table
once u find mole multiply it by Avogadro's number
& u'll get the answer
my answer is C. @Somy
You had asked this question 14 days back http://openstudy.com/study#/updates/54f2a546e4b006da7538b11c
But the answer is wrong :(
ah wait we are not done sorry i didnt notice the N part
so you find the total mole and of that total mole you have to find mole of N
show me your first part working mole finding with the answer
okay
\[CO(NH _{2})_{2}=60gmol^{-1}\]
\[\frac{ 60g }{ 60gmol^{-1} }=1mol\]
good now look 1 mole = whole compound molecular mass X mole = molecular mass of nitrogen
X mole = 1 mole x molecular mass of nitrogen / molecular mass of the whole compound
show me your next working using this
okay
\[1mol~\times2\times6\times10^{23}mol^{-1}=12\times10^{23}\]
\[=1.2\times10^{24}\]
no no, this current working good now look 1 mole = whole compound molecular mass X mole = molecular mass of nitrogen X mole = 1 mole x molecular mass of nitrogen / molecular mass of the whole compound
\[=\frac{ 1mol~\times28gmol^{-1} }{ 60gmol^{-1} }\]
yep
\[=0.5mol\]
now multiply by Avogadro constant
\[=0.5mol~\times6\times10^{23}\]
yep
\[=3\times10^{23}\]
yas! :3 i hope its correct?
coz if not than i'll be shocked lol
Answer in the book say it is C.
but C will be all atoms
while q is asking for N atoms only
i'll look through it again
ok
hmm you multiplied mole of the whole compound which was 1 mole by 2 did u do it because there are two N atoms in a compound?
yep
got it sorry thats my error http://prntscr.com/6h2t1n (different q but you can get whats going on)
there are 2 N atoms per molecule of CO(NH2)2
so we have to multiply by 2
u are correct :) sorry had some errors in memory :D
Thnx a lot @somy :)
lol more like, thank you for refreshing my memory :)
=]
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