Rational Equation
\[\frac{ 11 }{ 8x }-\frac{ 1 }{ x+3 }=\frac{ 3 }{ 4x }\]
first find a common denominator
Okay, but what about the x+3?
he means to find a common denominator for the left hand side, then you will multiply by that denominator on both sides, then solve for x
your denominators are 8x, x+3 and 4x
4x is a factor of 8x so the common denominator will be 8x*(x+3)
multiply each term by the common denominator. because the denominator will be the same you can equate the numerators. simplify and solve.
Here's s a simple example\[\frac{ a}{ b }+\frac{c}{d}=\frac{d}{d}*\frac{a}{b}+\frac{b}{b}*\frac{c}{d}= \frac{ad}{bd}+\frac{cb}{bd}=\frac{ad+cb}{bd}\] Now let a= 11, b = 8x, c= 1, d= x+3. Combine like terms when you're done.
Sorry, I had to go, but okay. @triciaal
11(x+3)-8x-6(x+3) =0 x=5
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