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does this series converge or diverge? sum from n=1 to infinity of log(n*sin(1/n) )
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@hartnn @dan815
$$ \Large{\sum_{n=1}^{\infty} \log(n\cdot \sin(1/n) ) }$$
By the comparison test, the series converges.
do you agree that sin(1/n) < 1/n
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it is true that sin x < x for x > 0 , where x is in radians
remember, arclength = radius * theta . Here radius is 1 . theta I labeled as x
you can see that geometrically, the arc of length x must be longer than sin x .
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