Mathematics
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OpenStudy (dtan5457):
Solutions for 3cosx=cosx-1
domain=0<=x<2pi
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OpenStudy (dtan5457):
should there be 4 solutions...?
OpenStudy (dtan5457):
1 per quadrant?
OpenStudy (dtan5457):
@dan815
OpenStudy (anonymous):
Nope! There should be 2 solutions tops
OpenStudy (dtan5457):
quadrant 2 and 3?
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OpenStudy (anonymous):
Yep! On the right track.
OpenStudy (anonymous):
Do you need a hint?
OpenStudy (dtan5457):
ok
OpenStudy (anonymous):
3cosx=cosx-1
2cosx=-1
cosx = -1/2 right?
OpenStudy (dtan5457):
mhm
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OpenStudy (anonymous):
So we are looking for the angle that gives us the point where x = -1/2
OpenStudy (anonymous):
Do you have a unit circle on you?
OpenStudy (dtan5457):
yes
OpenStudy (anonymous):
Look at the points where x is 1/2
OpenStudy (dtan5457):
2pi/3
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OpenStudy (dtan5457):
is that theta 60?
OpenStudy (anonymous):
and there is another one
OpenStudy (dtan5457):
what angle is this on a 30-60-90?
OpenStudy (anonymous):
Dont get ahead of yourself! Find the other angle too!
OpenStudy (dtan5457):
i'm just asking what angle its on a 30-60-90..we won't have unit circles on a test.
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OpenStudy (anonymous):
Yeah I memorized the circle. Um look at it like this|dw:1426466483928:dw|
OpenStudy (dtan5457):
60, got it.
OpenStudy (dtan5457):
if the question was cosx=1/2?
OpenStudy (dtan5457):
4 solutions?
OpenStudy (anonymous):
We know this because the coordinates are -1/2 , sqrt(3)/2
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OpenStudy (anonymous):
No 2 solutions
OpenStudy (anonymous):
Given that 0 > theta > 2pi
OpenStudy (anonymous):
Do you understand why?
OpenStudy (dtan5457):
has to be in the positive quadrants, right
OpenStudy (anonymous):
Yup