Question

please help!
fan medal and testimony
Quadrilateral BCDE is inscribed inside a circle as shown below. Write a proof showing that angles C and E are supplementary.
(pic below)

Answer 1

Many ways to do this, have you tried anything?

I guess you can think about cyclic quadrilateral theorem :)

Answer 2

I tried solving for arcs but I just started to confuse myself lol @iambatman

Answer 3

Okay, that sounds nice. Show us what you did.

Answer 4

I know that all shapes equal out to 360
I figured that across from each angle was the same.
all angles however are 180, right?
and doesn't supplementary mean equal to? im doubting my knowledge on the rules to solve this

Answer 5

The Measure of Angle C = ½ The Measure of Arc DEB
Make a similar statement about angle E.

Answer 6

it couldn't be 90.... idk honestly, this is confusing. I give up. @tkhunny

Answer 7

I didn't ask you to measure an angle or to give up. I asked you to make a similar statement about Ange E. One step at a time. No need to try to jump to the end.

Answer 8

I divided this shape into two.
CDE and EBC both equal 180 but together it is 360.
Therefore, B being 180 and D being 180, we know that so does C and E.
Telling us that this is supplementary.

Answer 9

that's all I got.

Answer 10

Very good, actually. Let's just clean it up a little.

The Measure of Angle C = ½ The Measure of Arc DEB
The Measure of Angle E = ½ The Measure of Arc BCD

Adding

The Measure of Angle C + The Measure of Angle E =
½ The Measure of Arc DEB + ½ The Measure of Arc BCD =
½(The Measure of Arc DEB + The Measure of Arc BCD) =
½(360º) =
180º

Thus: The Measure of Angle C + The Measure of Angle E = 180º

And this is the definition of Supplementary Angles.

See, you DO have stuff. Good work.

Answer 11

just needed a push.

Answer 12

...and you did great! :-)

Always show your work, even if you think it useless. It may give us a clue how to help you better.