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Mathematics 13 Online
OpenStudy (anonymous):

is the answer of this correct a constant force P =750 N acts on the body shown during only the first 6m of its motion starting from rest of coefficient of friction is 0.20, find the velocity of the body after it has moved a total distance of 9m answer: is this correct? With a force like that, the weight of the block becomes 1150N (1150=1600-750*3/5), and the horizontal force that provides acceleration is 600N. Since there's a friction force = (0,2)*(1150)= 230, the resultant force that accelerates the object becomes 370N, providing an acceleration equal to 370/(1600/9,8) = 2,27.

OpenStudy (anonymous):

Now you can work with the equation to find the speed after 6m: Vf^2 = Vi^2 +2a*d -> Vf^2 = 0 + 2(2,27)*(6) -> Vf=5,21 Then, the friction accelerates on the opposite direction, still with 230N, so again... Vf^2 = Vi^2 +2a*d -> Vf^2 = 5,21^2 +2*(-1,04)*3 -> Vf=4,57m/s

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