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Mathematics 15 Online
OpenStudy (zenmo):

Need help with a small simple simplification.

OpenStudy (zenmo):

\[(\sqrt{3}+1)/(1-\sqrt{3})\]

OpenStudy (zenmo):

How do you simplify this to get \[-2-\sqrt{3}\]?

OpenStudy (misty1212):

HI!!

OpenStudy (zenmo):

Hello

OpenStudy (xapproachesinfinity):

do you know how to distribute? see this and do the same \[(a+b)(a-b)=a^2-ab+ba-b^2=a^2-\cancel{ab}+\cancel{ab}-b^2=a^2-b^2\]

OpenStudy (misty1212):

i guess there is no way to get around that math teacher word "simplification" what they really mean is "rationalize the denominator" but i guess that is not in their vocabulary

OpenStudy (misty1212):

you have to multiply top and bottom by the conjugate of the bottom

OpenStudy (xapproachesinfinity):

oh hold on i miss read that lol

OpenStudy (misty1212):

\[\frac{\sqrt3+1}{\sqrt3-1}\times \frac{\sqrt3+1}{\sqrt3+1}\] is the start

OpenStudy (zenmo):

Thanks I got it now. Just need a quick refresher. Thanks all! :)

OpenStudy (xapproachesinfinity):

yes that is rationalizing the bottom just like @misty1212 said

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

OpenStudy (xapproachesinfinity):

i didn't pay attention to that slash there but at any rate you still needed to you what i wrote :)

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