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OpenStudy (zenmo):
\[(\sqrt{3}+1)/(1-\sqrt{3})\]
OpenStudy (zenmo):
How do you simplify this to get \[-2-\sqrt{3}\]?
OpenStudy (misty1212):
HI!!
OpenStudy (zenmo):
Hello
OpenStudy (xapproachesinfinity):
do you know how to distribute?
see this and do the same
\[(a+b)(a-b)=a^2-ab+ba-b^2=a^2-\cancel{ab}+\cancel{ab}-b^2=a^2-b^2\]
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OpenStudy (misty1212):
i guess there is no way to get around that math teacher word "simplification"
what they really mean is "rationalize the denominator" but i guess that is not in their vocabulary
OpenStudy (misty1212):
you have to multiply top and bottom by the conjugate of the bottom
OpenStudy (xapproachesinfinity):
oh hold on i miss read that lol
OpenStudy (misty1212):
\[\frac{\sqrt3+1}{\sqrt3-1}\times \frac{\sqrt3+1}{\sqrt3+1}\] is the start
OpenStudy (zenmo):
Thanks I got it now. Just need a quick refresher. Thanks all! :)
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OpenStudy (xapproachesinfinity):
yes that is rationalizing the bottom just like @misty1212 said
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
OpenStudy (xapproachesinfinity):
i didn't pay attention to that slash there
but at any rate you still needed to you what i wrote :)