Question

Radicals: See Comments

Answer 1

\[y ^{2/3}+12=7y ^{1/3}\]

Answer 2

HI!!

Answer 3

the gimmick is to think of this as a quadratic equation in \(y^{\frac{1}{3}}\)

Answer 4

put say \(x=y^{\frac{1}{3}}\) then solve
\[x^2+12=x\]

Answer 5

solve as normal for a quadratic equation
\[x^2-x+12=0\] factor etc
then once you have solved for \(x\) replace \(x\) by \(y^{\frac{1}{3}}\) and solve for \(y\)

Answer 6

you got this or no?

Answer 7

\[\sqrt[3]{-3}\]

Answer 8

\[\sqrt[3]{4}\]

Answer 9

you got it backwards i think

Answer 10

\[y^{\frac{1}{3}}=-3\\
y=(-3)^3\]

Answer 11

also for the four

Answer 12

got that?

Answer 13

-27, 64

Answer 14

yes i think so

Answer 15

awesome thanks again :)

Answer 16

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