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Mathematics 20 Online
OpenStudy (anonymous):

@misty1212

OpenStudy (anonymous):

OpenStudy (misty1212):

\[h(t)=-16t^2+20t+2\] right?

OpenStudy (anonymous):

yes

OpenStudy (misty1212):

max occurs at the vertex first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\) which in your case is \[-\frac{20}{2\times (-16)}\]

OpenStudy (misty1212):

the closest number you have in your answer choices is \(.63\) so you don't have to do any more work, there is only one choice there

OpenStudy (anonymous):

so B?:)

OpenStudy (anonymous):

thank you. and the second one?

OpenStudy (misty1212):

let me look

OpenStudy (misty1212):

you can do that just like the last one compute \(-\frac{b}{2a}\) and tell me what you get

OpenStudy (anonymous):

-184/-32

OpenStudy (anonymous):

5.75

OpenStudy (misty1212):

ok now you have two choices

OpenStudy (misty1212):

put \(t=5.75\) and see what you get use a calculator

OpenStudy (anonymous):

i got 549

OpenStudy (misty1212):

then go with that one

OpenStudy (anonymous):

thanks

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

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