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@misty1212
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\[h(t)=-16t^2+20t+2\] right?
yes
max occurs at the vertex first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\) which in your case is \[-\frac{20}{2\times (-16)}\]
the closest number you have in your answer choices is \(.63\) so you don't have to do any more work, there is only one choice there
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so B?:)
thank you. and the second one?
let me look
you can do that just like the last one compute \(-\frac{b}{2a}\) and tell me what you get
-184/-32
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5.75
ok now you have two choices
put \(t=5.75\) and see what you get use a calculator
i got 549
then go with that one
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thanks
\[\color\magenta\heartsuit\]
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