Question

Which of the following x-coordinates is a candidate for being an extreme value for the function f(x)=x^2 2^x
a) -1, b) 2, c) 1, d) 0

Answer 1

\[f(x)=x^2 2^x\]

Answer 2

The derivative is f'(x)=2x2^xln2, I don't know where to go from there

Answer 3

find the critical values

Answer 4

by equating the derivative to 0

Answer 5

0=2x2^x ln2
0=2x2^x
is that right so far?

Answer 6

yep

Answer 7

Ok now i'm not too sure what to do. would I remove the 2 from 2x?

Answer 8

Oh wait would I do 2x=0 then x=0. Then I sub in the x=0 into 2^x?

Answer 9

wait

Answer 10

are u sure abt ur derivative

Answer 11

I'm not too sure but I think it's right

Answer 12

k