can any one help me with this question please!
What is it?
Eh, i dont want to download it sorry
Do you have pictures?
ok I will try to type it!
ok
Calculate the Delta H reaction for the reaction below: N2H4(L)+ O2(g)-----> N2(g)+ 2H2(L) Given: 1-2NH3(g)+3N2O(g)----> 4N2(g)+3H2O(L) Delta H rxn=-1010KJ 2-N2O(g)+3H2(g)-------> N2H4(l)+H2O(L) Delta H rxn=-317KJ 3-2NH3(g)+1/2O2(g)----->N2H4(l)+H20(l) delta H rxn =-143Kj 4-H2(g)+1/2O2(g)----->H20(l) Delta H rxn= -286kj
OH
Ok i got this
sorry I typed the wrong question than I retyped the correct one :( thanks alex for your patient !!
Let me write it out wait up, i just got done studying this
Thank you I am trying to understand it,but I couldn't !
you just have to switch the equations around to get delta H, you want to get the right reactants on one side and the right products on the other, so you switch them around, cancel the ones you dont need if theyre the same. Once you switch the equation the Delta H is also switched
Did you write the numbers infront of the equations given 1-4, or did they give you them
they gave it is Roman numbers
do I flip them all or only 2 and 3?
for 2 and 3 i think you have to multiply by 1/2
and switch them
so the N2H4 add up to one
Ok I will try it out
This isnt adding up
It is not adding up :(
Im getting left with extra n20, and h2
You cant get a picture using the snipping tool?? I want to see if everything is correct, because the values arnt cancelling out
I dont see the snipping tool??
What type of computer do you have
apple mac
Im having trouble with the N2 because its asking for 1 mol of product, but the chemical reactions only show 1 N2 with 4 mol of product, so youd have to divid the delta H by 4 to get 1 mole of N2, but it would make the N20 and the H20 decimals.
I double checked it and that's how the question was given, I did get decimals too..
let me ask my friend
thanks Alex, I will keep trying ... hopefully I will get it
Yeah because if we divide the N2 by four to get the 1 mol of product, we would have to divide the other equations to cancel out the H20 and N20
By when do you need this done
By Tuesday
Alright, Im going to ask about it tomorrow to my prof. If no one answers it by tomorrow afternoon i will have an answer for you
Great ! I am going to seek help from tutors tomorrow, and I will check it with you after noon thanks a lot for you help!
Yup you too, i want to learn about it as well, see you tomorrow!
ok see you :)
I got it when I added them at the end I divided by 4
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