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Chemistry 11 Online
OpenStudy (anonymous):

can any one help me with this question please!

OpenStudy (anonymous):

What is it?

OpenStudy (anonymous):

OpenStudy (anonymous):

Eh, i dont want to download it sorry

OpenStudy (anonymous):

Do you have pictures?

OpenStudy (anonymous):

ok I will try to type it!

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Calculate the Delta H reaction for the reaction below: N2H4(L)+ O2(g)-----> N2(g)+ 2H2(L) Given: 1-2NH3(g)+3N2O(g)----> 4N2(g)+3H2O(L) Delta H rxn=-1010KJ 2-N2O(g)+3H2(g)-------> N2H4(l)+H2O(L) Delta H rxn=-317KJ 3-2NH3(g)+1/2O2(g)----->N2H4(l)+H20(l) delta H rxn =-143Kj 4-H2(g)+1/2O2(g)----->H20(l) Delta H rxn= -286kj

OpenStudy (anonymous):

OH

OpenStudy (anonymous):

Ok i got this

OpenStudy (anonymous):

sorry I typed the wrong question than I retyped the correct one :( thanks alex for your patient !!

OpenStudy (anonymous):

Let me write it out wait up, i just got done studying this

OpenStudy (anonymous):

Thank you I am trying to understand it,but I couldn't !

OpenStudy (anonymous):

you just have to switch the equations around to get delta H, you want to get the right reactants on one side and the right products on the other, so you switch them around, cancel the ones you dont need if theyre the same. Once you switch the equation the Delta H is also switched

OpenStudy (anonymous):

Did you write the numbers infront of the equations given 1-4, or did they give you them

OpenStudy (anonymous):

they gave it is Roman numbers

OpenStudy (anonymous):

do I flip them all or only 2 and 3?

OpenStudy (anonymous):

for 2 and 3 i think you have to multiply by 1/2

OpenStudy (anonymous):

and switch them

OpenStudy (anonymous):

so the N2H4 add up to one

OpenStudy (anonymous):

Ok I will try it out

OpenStudy (anonymous):

This isnt adding up

OpenStudy (anonymous):

It is not adding up :(

OpenStudy (anonymous):

Im getting left with extra n20, and h2

OpenStudy (anonymous):

You cant get a picture using the snipping tool?? I want to see if everything is correct, because the values arnt cancelling out

OpenStudy (anonymous):

I dont see the snipping tool??

OpenStudy (anonymous):

What type of computer do you have

OpenStudy (anonymous):

apple mac

OpenStudy (anonymous):

Im having trouble with the N2 because its asking for 1 mol of product, but the chemical reactions only show 1 N2 with 4 mol of product, so youd have to divid the delta H by 4 to get 1 mole of N2, but it would make the N20 and the H20 decimals.

OpenStudy (anonymous):

I double checked it and that's how the question was given, I did get decimals too..

OpenStudy (anonymous):

let me ask my friend

OpenStudy (anonymous):

thanks Alex, I will keep trying ... hopefully I will get it

OpenStudy (anonymous):

Yeah because if we divide the N2 by four to get the 1 mol of product, we would have to divide the other equations to cancel out the H20 and N20

OpenStudy (anonymous):

By when do you need this done

OpenStudy (anonymous):

By Tuesday

OpenStudy (anonymous):

Alright, Im going to ask about it tomorrow to my prof. If no one answers it by tomorrow afternoon i will have an answer for you

OpenStudy (anonymous):

Great ! I am going to seek help from tutors tomorrow, and I will check it with you after noon thanks a lot for you help!

OpenStudy (anonymous):

Yup you too, i want to learn about it as well, see you tomorrow!

OpenStudy (anonymous):

ok see you :)

OpenStudy (anonymous):

I got it when I added them at the end I divided by 4

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