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Mathematics 6 Online
OpenStudy (anonymous):

At 9am ship A is 50km east of the ship B. Ship A is sailing north a 40km/h and Ship B is sailing south at 30km/h. Howfast is the distance between them changing at noon?

OpenStudy (nincompoop):

draw first

OpenStudy (anonymous):

I'm not sure how to draw it. It looks weird

OpenStudy (nincompoop):

|dw:1426484330996:dw|

OpenStudy (nincompoop):

set up your equations

OpenStudy (nincompoop):

|dw:1426484429087:dw|

OpenStudy (nincompoop):

so this is quite similar with falling or sliding ladder problems

OpenStudy (nincompoop):

figure out the plan of attack then post here what you came up with

OpenStudy (anonymous):

I have no clue... Is there two right triangles in this?

OpenStudy (nincompoop):

there are two triangles, correct. that is if you want to see it that way

OpenStudy (nincompoop):

you are looking for the \(\sf \large s\) between the two ships and the only way to really do that is to draw a straight line between them continuously from 9AM till 12PM

OpenStudy (anonymous):

Do we need to figure the distances of A and B?

OpenStudy (nincompoop):

that's what it is asking eventually, the distance between two ships - but at what rate they are going farther away from each other

OpenStudy (anonymous):

I'm not sure how to do this...

OpenStudy (anonymous):

We need to use this: a^2+b^2=c^2 ??

OpenStudy (nincompoop):

ye

OpenStudy (anonymous):

Do we need to divide 50 by 2?

OpenStudy (anonymous):

@nincompoop

OpenStudy (nincompoop):

I really need for you to think this hard

OpenStudy (anonymous):

Can you give me another hint?

OpenStudy (anonymous):

I got these numbers 5sqrt601 and 5sqrt349

OpenStudy (anonymous):

Really don't get this, can you please explain it...

OpenStudy (anonymous):

What am I finding? Like I got sqrt (120^2+25^2) which is 5sqrt601

OpenStudy (anonymous):

:(

OpenStudy (dan815):

-.-

OpenStudy (dan815):

forget related rates right now

OpenStudy (dan815):

first things first, can you draw the right picture

OpenStudy (dan815):

and do you know the geometry of this problem

OpenStudy (dan815):

the idea of related rates is very simple if Dan moves 2 steps for every step NIN takes and if nin is taking 10 steps a min Then I must be taking 20 steps a min as iam taking 2 stesp for every step nin takes

OpenStudy (dan815):

The same idea is applied here

OpenStudy (dan815):

herse another way to see what is going on maybe it will help u visualize better

OpenStudy (dan815):

the horizontal distance is the same all the time but the vertical distance is changing so

OpenStudy (dan815):

|dw:1426487803001:dw|

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