Sulphur dioxide is produced according to the following equation. @Somy

Question

anonymous · Answer

$$S(s)+O _{2}(g)\rightarrow~SO _{2}(g)$$

anonymous · Answer

What is the volume of gas produced if 448cm^3 of oxygen gas reacts at STP?[1mol of gas occupies 22.4dm^3 at STP]

anonymous · Answer

A 112cm^3
B 224cm^3
C 448cm^3
D 896cm^3

somy · Answer

oh sorry, i will be free in 7 hours

somy · Answer

sorry just got free

somy · Answer

well the ratio between O2 and sulfur dioxide is 1:1 
thus mole is same 
and if mole is same 
then volume produces is same since we'll multiply it to same condition STP

anonymous · Answer

$$448+448=896$$

somy · Answer

i thought it'd stay same tho?

somy · Answer

is the ans in your book 896?

thadyoung · Answer

If it is given at STP, it is 22.4 mol per liter.
Use that relationship to solve for volume .
Convert liters to cm$^3$

anonymous · Answer

Sorry 4 the late reply,the answer is C. @Somy

somy · Answer

thats what i told you

somy · Answer

but why did u double it?

somy · Answer

" well the ratio between O2 and sulfur dioxide is 1:1 
thus mole is same 
and if mole is same 
then volume produces is same since we'll multiply it to same condition STP "

read it again

anonymous · Answer

i add up bcoz $$SO _{2}=S+O _{2}$$$$SO_{2}=448+448$$$$SO _{2}=896$$

somy · Answer

it doesnt work that way 
you see at mole ratio 
between SO2 and O2 
and accordingly get to see mole difference 
here mole ratio between the two (since we are not given actual moles, we look at coefficients) 
is 1:1 
thus we can assume that mole is same for both 
so now think 
formula is 
Volume = mole x STP volume 
so we know STPvolume 
and also 
we know that their moles are same 
thus volume will be same also

anonymous · Answer

Thanks a lot @Somy :)

somy · Answer

no problem :D