http://maxpapers.com/wp-content/uploads/2012/11/9701_w14_qp_12.pdf q30
Is the answerC?
that's what i have thought at the beginning but it turned out to be B
Ok, let me see it. That's the exam paper I did last year though...
oh take your time, so how was your grade?
Was an A.
congrats on that (Y). Have you got any practical notes?
You mean for paper 3?
Thanks.
yes, your welcome.
Practically not. We just made notes on how to make tables very accurately.
i am retaking AS level chemistry on this june . I scored a U im my practicals but scored two A's in my other two papers and i will be doing A2(not a retake) next to it too.
I think I got it why is it B now. You should know that when unsaturated parts react with hot KMnO4, this first breaks the double bond into a diol and the OH parts eventual turn into a carboxylic acid group or ketone groups. As for all unsaturated parts out of the two enclosed structures, the double bonds after breaking will have two free more bonds to make, hence they can be carboxylic acid. As for the ones inside the enclosed part, they only have 1, because the 2 other parts are already bonded to the carbon, so it will make a double bond with an oxygen, making a ketone. Each unsaturated part inside the enclosed structure can make 3 different ketones, giving a total f 6.
Good luck then. So you will be doing papers 3, 2 and 5 right?
no, i have to repeat all papers :( . in addition to paper 4 and paper 5. well, if it has one hydrogen bonded to a carbon atom, the molecule would be oxidized into an alcohol and eventually further oxidises into a carboxylic acid.
Correct.
Red arrows is where i think ketones would be produced, only C atoms attatched to CH3 and to the rest of the chain.
not the other carbon atom bonded to a hydrogen atom
Within your red arrows, only the ones pointing at the double bond inside the enclosed structured will turn into a ketone, because they have 2 fixed bonds already to the Carbon and thus if it oxidises, it can convert the other 2 into a ketone, whereas for the others, the Carbon will be having only 1 fixed bond and with the 3 free, it makes a carboxylic acid.
The starting C=C and the ending C=C do turn into a ketone, yes?
Yes and each of them makes 3 different ketones.
shouldnt it be 4 ketones
No. In each of them, the part of the double bond attached directly to CH3 can only make one, whereas the other end can make 2.
i am talking about the double bond at each end of the structure, yes they will produce 2 different ketones, and the C=C bonded to CH3 will only be oxidised to a ketone the other C atom wont.
Yes.
How is that a 6 molecule then.
Let me recap. The correct arrows are the ones pointing at the double bonds inside the enclosed structures and each one of them makes 3 different ketones, making a total of 6 .
okay, three different ketons are the C=C at the end the 3rd C=C and the 3rd is?
O. They are in your first and last showed arrows.
The C=C at each end are the same its just rotated, they should be the same i think.
Yes, they are.
they should produce the same ketons then.
Yes.
2nd and 5th arrow are also the same right they would produce the same ketone but here only one carbon atom is oxidised.
same goes to the 3rd and 4th arrow right?
Yes, but those ones would form carboxylic acid instead of ketones, as I said before.
i am not saying that two C atoms involved in double bonding will form a ketone but only the carbon atom attatched to CH3 will form a ketone. we should take this into account.
Oh, yes. You got it.
i counted the one carbon atom being oxidised as whole different molecule. Thanks for your help and time :)
No problem. Hope you do well this June. I will keep on praying for you.
Thanks, same here :)
Join our real-time social learning platform and learn together with your friends!