Question

Logx=Log2x^2-2

Answer 1

I need help

Answer 2

\[\log(x) = \log_{2}(x^2)-2\]
Is this right?

Answer 3

Or:
\[\log(x) = \log(2x^2)-2\]

Answer 4

it's the second one

Answer 5

@eta

Answer 6

Good..

Answer 7

Subtract \(\log(x)\) from both the sides..

Answer 8

Is x=50

Answer 9

\[\log(x) = \log(2x^2)-2 \\ \log(x)-\log(x) = \log(2x^2)-2-\log(x) \\ 0 = \log(2x^2)-\log(x)-2\]
Add \(2\) both the sides now:

Answer 10

\[0+2 = \log(2x^2)-\log(x)-2+2 \\2 = \log(2x^2)-\log(x)\]

Answer 11

Now use property of logarithm:
\[\log(a)-\log(b)=\log(\frac{a}{b})\]

Answer 12

So:
\[2= \log(\frac{2x^2}{x}) \\ 2 = \log(2x)\\ 10^2 = 2x \\ \color{green}{x = 50}\]

Answer 13

Good, yes you are right.. :)

Answer 14

thank you so much just wanted to make sure i was right

Answer 15

You are..!!