Question

x^2 -2x-62=0
A. x=-1+-3(sqrt 7)
B. x=1+-3(sqrt 7)
C. x=2+_6(sqrt7)
D. no real sol

Answer 1

there are two ways
either complete the square or use the quadratic formula

completing the square

\[x^{2} + bx + c=0\]
to complete the square
\[(x+\frac{ b }{ 2 })^{2}-(\frac{ b }{ 2 })^{2} + c=0\]

in your case
b=-2
c=-62

Answer 2

rearrange to work out your answer

Answer 3

I did that but I keep getting two answers and I neeed to pick one but I don't know which one @amorfide

Answer 4

using the formula I gave you

\[(x+\frac{ -2 }{ 2 })^{2} - (\frac{ -2 }{ 2 })^{2} - 62 = 0\]
\[(x-1)^{2} - 1 - 62=0\]
\[(x-1)^{2} -63=0\]
\[(x-1)^{2}=63\]

Answer 5

you can work out the rest yourself

Answer 6

show me what you get and I will help