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OpenStudy (jojokiw3):
How do I do this Trigonometry question?
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OpenStudy (jojokiw3):
\[\sec(-\frac{ 3 \pi}{ 4 }) -\cot \frac{ \pi }{ 2 } + \csc \frac{ 3 \pi }{ 2 }\]
OpenStudy (welshfella):
use the identities
sec = 1/cos, cot=1/tan and csc = 1/sin
then its a matter of plugging the values into your calculator
OpenStudy (welshfella):
to find cot pi/2:- find tan pi/2 - say its comes to 0.5 then cot pi/2 = 1/0.5
OpenStudy (jojokiw3):
Wait so I must find the tangent of 90 degrees then? Since pi/2 is technically 90 degrees?
OpenStudy (welshfella):
yes the angles are given in radians - so you set your calculator to radians or do the conversion
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OpenStudy (welshfella):
oh hold on tan pi/2 is indeterminate as it = 1/0 but the cot is 0/1 so that is 0
OpenStudy (welshfella):
you are correct about sec = -sqrt2
OpenStudy (welshfella):
now find sin (3pi/2)
OpenStudy (jojokiw3):
0?
OpenStudy (welshfella):
no not 0
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OpenStudy (welshfella):
sin(3pi/2) i meant
OpenStudy (jojokiw3):
-1.
OpenStudy (jojokiw3):
\[-\sqrt{2} - 1\]
OpenStudy (welshfella):
Jojokiw3 has given you the answer but I would have preferred if you had found it yourself
OpenStudy (jojokiw3):
Well it's my question. o_O
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OpenStudy (welshfella):
oh sorry yes
OpenStudy (jojokiw3):
haha lol. Thanks!
OpenStudy (welshfella):
lol yw
OpenStudy (welshfella):
i somehow mixed you up with the other guy!
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