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Mathematics 7 Online
OpenStudy (anonymous):

Will fan+medal What are the coordinates of the vertex of the graph of the function y=-x^2+6x-11 what are the coordinates of the vertex of the graph of the function y=-3x^2-12x+3 Which graph represents the function 3x^2+12x-6 Which equation matches the graph shown below? https://www.connexus.com/content/media/456845-3112011-33137-PM-495084547.png Which of the following functions has a rate of change that stays the same?

OpenStudy (anonymous):

@TheSmartOne

TheSmartOne (thesmartone):

To find the vertex of \(\sf ax^2+bx+c\) use the formula \(\sf\large h=\frac{-b}{2a}\) And then plug h back in to your equation and the vertex will be \(\sf (h, f(h) )\)

OpenStudy (anonymous):

@Thatonegirl_

OpenStudy (anonymous):

ill fan+medal

OpenStudy (thatonegirl_):

You don't know any of these??

OpenStudy (anonymous):

nope

OpenStudy (thatonegirl_):

well the 1st and 2nd r practically the same so I'll tell u how to do the first

OpenStudy (thatonegirl_):

Do you have the formula for the vertex?

OpenStudy (anonymous):

i know the first one is x=1

OpenStudy (thatonegirl_):

The x coordinate?

TheSmartOne (thesmartone):

I stated it above.

OpenStudy (anonymous):

no the y sorry

OpenStudy (thatonegirl_):

Well to find the Y you need to plug the X into the original equation, right?

OpenStudy (anonymous):

the second i think is (-3,-20)

OpenStudy (anonymous):

Yea i did that

OpenStudy (anonymous):

thats how i know that the first one is right (hopefully)

TheSmartOne (thesmartone):

Your equation is in the form of \(\sf ax^2+bx+c\) so it's vertex is \(\sf\large(\frac{-b}{2a},(\frac{-b}{2a}))\)

OpenStudy (thatonegirl_):

the x coordinate formula is the opposite of b over 2 times a. \[\frac{ -b }{ 2a }\]

OpenStudy (anonymous):

ok so plug in the numbers?

OpenStudy (thatonegirl_):

yup. a=-1 and b=6

OpenStudy (anonymous):

is that the answer or do we have to solve ?

OpenStudy (anonymous):

the secind one am i right?

OpenStudy (anonymous):

hello????

OpenStudy (thatonegirl_):

Sorry, and yes now plug that in for x to find y=

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