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OpenStudy (anonymous):
What value of x satisfies cot (90° − x) = 1?
11 years ago
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OpenStudy (anonymous):
60°
135°
225°
315°
11 years ago
OpenStudy (anonymous):
@saifoo.khan
11 years ago
OpenStudy (anonymous):
@dan815
11 years ago
OpenStudy (anonymous):
@iGreen
11 years ago
OpenStudy (anonymous):
@Compassionate
11 years ago
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OpenStudy (anonymous):
Precalc
11 years ago
OpenStudy (anonymous):
cotangent
11 years ago
OpenStudy (anonymous):
degrees
11 years ago
OpenStudy (welshfella):
Hint: cot = 1 / tan
11 years ago
OpenStudy (anonymous):
?
11 years ago
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OpenStudy (jdoe0001):
\(\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{\color{red}{ \theta}}\right)=cos({\color{red}{ \theta}})\qquad
cos\left(\frac{\pi}{2}-{\color{red}{ \theta}}\right)=sin({\color{red}{ \theta}})
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{\color{red}{ \theta}}\right)=cot({\color{red}{ \theta}})\qquad
cot\left(\frac{\pi}{2}-{\color{red}{ \theta}}\right)=tan({\color{red}{ \theta}})
\\ \quad \\ \quad \\
cot(90^o-{\color{red}{ x}})=1\implies tan({\color{red}{ x}})\implies tan^{-1}[tan({\color{red}{ x}})]=tan^{-1}(1)
\\ \quad \\
{\color{red}{ x}}=tan^{-1}(1)\)
11 years ago
OpenStudy (anonymous):
135?
11 years ago
OpenStudy (jdoe0001):
well... .recall that tangent is really \(\bf tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{{\color{brown}{ sin}}(\theta)}{{\color{blue}{ cos}}(\theta)}\)
and 135 degree angle is in the 2nd Quadrant
on the 2nd quadrant "y" is positive, and "x" is negative
so y/x will mean -1 for a \(\bf tan(135^o\)
11 years ago
OpenStudy (jdoe0001):
\(\bf tan(135^o)\) =)
11 years ago
OpenStudy (jdoe0001):
so... is not 135
11 years ago
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OpenStudy (anonymous):
ok
11 years ago
OpenStudy (anonymous):
225
11 years ago
OpenStudy (anonymous):
thx
11 years ago
OpenStudy (jdoe0001):
yw
11 years ago
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