The velocity of a particle moving along a line is t2 - 2t sin(t2 ) meters per second. The net change in the particle's position during the time interval 0 ≤ t ≤ 4 is given by:
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OpenStudy (nathanjhw):
OpenStudy (nathanjhw):
@saifoo.khan
OpenStudy (nathanjhw):
@jdoe0001
OpenStudy (anonymous):
If the time derivative of a position-time graph gives velocity, then the integral (i.e. area under the curve) of a velocity-time graph gives position as a function of time.
OpenStudy (anonymous):
So what are your limits of integration ? Hint: the question tells you...
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OpenStudy (nathanjhw):
(4,0)
OpenStudy (nathanjhw):
sorry (0,4)
OpenStudy (anonymous):
Good, what are you integrating with respect to ? Is is time?
OpenStudy (nathanjhw):
Velocity?
OpenStudy (anonymous):
No. What does (0,4) represent?
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OpenStudy (nathanjhw):
Oh time.
OpenStudy (anonymous):
Correct , so our differential is \[dt\] , and our limit is \[\int\limits_{0}^{4}\] . The answer should be obvious now !
OpenStudy (nathanjhw):
It should be integral (0,4) t^2-2tsin(t^2) dt
OpenStudy (anonymous):
Correct :)
OpenStudy (nathanjhw):
Now if I wanted to calculate the actual net change in position to find the value in meters would I just solve the above integral?
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OpenStudy (anonymous):
Yes, that would give you the net change in position between 0 and 4 seconds.