Question

Simplify.

Answer 1

\[\frac{ a }{ \sqrt{b} }=\frac{ a \sqrt{b} }{ \sqrt{b}\sqrt{b} }\]

Answer 2

multiply top and bottom by sqrt20
then you can simplify from there

Answer 3

u can write it as
\[\frac{ \sqrt{5} \sqrt{x} }{ x \sqrt{5} \sqrt{4} }\]

Answer 4

\(\bf \cfrac{\sqrt{5x}}{x\sqrt{20}}\implies\cfrac{\sqrt{5\cdot x}}{x\sqrt{5\cdot 2\cdot 2}}\implies \cfrac{\sqrt{5}\cdot \sqrt{x}}{x\sqrt{5}\cdot\sqrt{2^2}}\implies ?\)

Answer 5

hmm actually.... lemme redo that a bit

Answer 6

\(\bf \cfrac{\sqrt{5x}}{x\sqrt{20}}\implies\cfrac{\sqrt{5}\cdot \sqrt{x}}{\sqrt{x^2}\sqrt{5\cdot 2\cdot 2}}\implies \cfrac{\sqrt{5}\cdot \sqrt{x}}{\sqrt{x^2}\sqrt{5\cdot 2^2}}
\\ \quad \\
\cfrac{\sqrt{5}\cdot \sqrt{x}}{\sqrt{x}\cdot \sqrt{x}\cdot \sqrt{5}\cdot \sqrt{2^2}}\implies ?\)

Answer 7

how did u get \[\sqrt{x ^{2}}\] on the bottom fraction?

Answer 8

well... what's \(\large \sqrt{x^2}=?\)

Answer 9

\[\sqrt{x ^{2}} = x\]

Answer 10

there
\(\bf \cfrac{\sqrt{5x}}{x\sqrt{20}}\qquad {\color{brown}{x\iff \sqrt{x^2} }}\implies\cfrac{\sqrt{5}\cdot \sqrt{x}}{\sqrt{x^2}\sqrt{5\cdot 2\cdot 2}}\implies \cfrac{\sqrt{5}\cdot \sqrt{x}}{\sqrt{x\cdot x}\sqrt{5\cdot 2^2}}
\\ \quad \\
\cfrac{\sqrt{5}\cdot \sqrt{x}}{\sqrt{x}\cdot \sqrt{x}\cdot \sqrt{5}\cdot \sqrt{2^2}}\implies ?\)

Answer 11

so would the answer be \[\left(\begin{matrix}\sqrt{x} \\ 2x\end{matrix}\right)\] ?

Answer 12

The three answers i have to choose from are
A. \[\left(\begin{matrix}1 \\ 2\end{matrix}\right)\]
B. \[\left(\begin{matrix}\sqrt{x} \\ 2x\end{matrix}\right)\]
C. \[\left(\begin{matrix}\sqrt{x} \\ 2\end{matrix}\right)\]

Answer 13

well
cancel what you can from the fraction, whatever you're left with, is that