Question

HELP!!!
IM GOING TO POST Q IN AN ATTACHMENT!

Answer 1

wait jus a sec ima post it

Answer 2

lolzz i know

Answer 3

hmm *4 days ago*
lol when you gonna post that lol :)
(: o^_^o

Answer 4

ima post it rn

Answer 5

lolzzz my bad thoo

Answer 6

hmm well seee
4 days more ?

Answer 7

lolzzz no girl
im doin it rn

Answer 8

Are you having trouble attaching the file?

Answer 9

yess

Answer 10

What kind of file is it?

Answer 11

hold on ima try again k

Answer 12

FINALLY I GOT IT UP THERE LOL

Answer 13

Ax^2 +Bx+C=0
quadratic equation
if A is negative then graph should have minimum point
and if A is positive then graph should have maximum point
i hve to refresh page bec draw tO_Ol doesn't work

Answer 14

Let's go over each point and use the graph to help you.

A-The graphs of two of the functions have a minimum point.
A NEGATIVE "A" value, it will have a maximum point. You have two negative functions here...

B-The same axis of symmetry
The axis of symmetry can be defined as -b/2a, which you can tell all of them are 0 here.

C-The graphs of two of the functions do not cross the x axis.
Look at the graph.

D-Different y intercepts

considering y=mx+b

all b values are different.

Answer 15

@Nnesha Wouldn't a negative function have a maximum point?

Answer 16

for axis of symmetry
use formula \[\huge\rm \frac{ -b }{ 2a }\]
Ax^2 +bx+C= 0
^a ^b