Question

1+cosx=sqrt3(sinx)

Answer 1

@freckles

Answer 2

\[1+\cos(x)=\sqrt{3} \sin(x)\]

Answer 3

I suggest squaring both sides so we can write fully in terms of cos(x) or just sin(x)
I think you will find we will need to write in terms of cos(x)
you will have a quadratic again

Answer 4

could i somehow divide cos to make sin/cos and call it tan?

Answer 5

@freckles

Answer 6

@jim_thompson5910 @Nnesha

Answer 7

so then you would have sec(x)+1=sqrt(3) tan(x)

Answer 8

that looks uglier :p

Answer 9

ok then square both sides

Answer 10

lol

Answer 11

3sinx^2=cosx^2+2cosx+1

Answer 12

\[\sin^2(x)=1-\cos^2(x)\]

Answer 13

you will have a quadratic in terms of cos(x)

Answer 14

wait what lol isn't squaring both sides

(1+cosx)(1+cosx)=(sqrt3sinx)(sqrt3sinx)

Answer 15

yea you did it right
now just replace sin^2(x) with (1-cos^2(x)) to get your quadratic in terms of cos(x)

Answer 16

lol i don't remember my identities, sin^2x=1-cos^2x?

Answer 17

that is a pythagorean identity

Answer 18

ooh yeah i see it now