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Mathematics 18 Online
OpenStudy (mathmath333):

Their are two circles with Center A and B with radius \(40\) m and \(80\) m respectively such that they meet at point x externally. Bolt runs at \(80\pi\) m/min on circle A. Paul runs at \(40\pi\) m/min on circle B. Both of them start at point x and run multiple rounds. If Bolt gives Paul start of \(4\) min exactly before he starts running himself. After how much time will the straight line between them will be \(240\) m.

OpenStudy (rational):

that looks hard http://i.ytimg.com/vi/ItWI9nVtS-s/maxresdefault.jpg

OpenStudy (mathmath333):

no

OpenStudy (mathmath333):

|dw:1426583556554:dw|

OpenStudy (abb0t):

So, the point where two points meet is known as the vertex, yes?

OpenStudy (alekos):

I get 1 min

OpenStudy (ikram002p):

so just one question i have, at which direction P and B runs ? like we have 4 choices here i can't determine which direction to take :P

OpenStudy (alekos):

I don't think direction matters in this case

OpenStudy (mathmath333):

direction doesnt matter

OpenStudy (ikram002p):

well :P lets solve it geometrically (i don't know yet if its matter or not at least it matter to me )

OpenStudy (mathmath333):

\(\large \color{black}{ a.)\quad 6 \quad min\hspace{.33em}\\~\\ b.)\quad 10 \quad min\hspace{.33em}\\~\\ c.)\quad 12.5 \quad min\hspace{.33em}\\~\\ d.)\quad none \quad \hspace{.33em}\\~\\ }\)

OpenStudy (ikram002p):

|dw:1426585187838:dw|

OpenStudy (ikram002p):

so as been said 240 m as graph this is the only case that could be (y,z) it cant be x1 and z1(at any place since distance would be less than 240)

OpenStudy (alekos):

That's right. And it take s them both 1 minute to get to y and z respectively

OpenStudy (ikram002p):

:)

OpenStudy (ikram002p):

so i can say only in this case direction seems does not matter otherwise ;P it is

OpenStudy (mathmath333):

@alekos if u think its \(1\) min , then prove it.

Miracrown (miracrown):

The two circles are tangent?

OpenStudy (ikram002p):

ok so paul start at x, parameter of the circle B \(160\pi\) so for full loop time = 160 pi/ 40 pi = 4 mints for Bolt start at x , parameter of the circle A \(80 \pi\) so for full loop time=80 pi/80 pi=1 mint |dw:1426585809793:dw|

OpenStudy (alekos):

Theres your proof!

OpenStudy (ikram002p):

so at 4 mints both start from x and they can reach y,z at these time (after 4 mints ) Pual Bolt 2 0.5 6 1.5 10 2.5 ... ... hmmm idk if they can ever met :O

OpenStudy (mathmath333):

the earlier work done by ikram shows \(1\) min for bolt to reach at point x.

Parth (parthkohli):

So they have got to be diametrically opposite to do so. We can use the equations of circular motion, I think...\[\theta = \omega t \]Here, \(\omega_{Bolt } = 2\pi ~\rm rad/min\) and \(\omega_{Paul} = \pi/4 ~\rm rad/min\). So the number of minutes will have to be a decimal.

Parth (parthkohli):

Why decimal? If it is integral, then Bolt will be at point x.

OpenStudy (ikram002p):

yeah @mathmath333 so i would say they never meet :P i'll see what mira and pk have :)

Miracrown (miracrown):

|dw:1426586246233:dw|

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