Question

You have a 2.00 kg block of lead. Lead melts at 327.5°C. CPb = 130.0 J/kg°C, and (delta)Hf for lead is 2.04 × 10^4 J/kg. Say you start at room temperature (25.0°C). How much heat must you transfer to melt all the lead?

Answer 1

Heat needed to get 327.5 degree celcius
Q=m*Cpb*(327.5-25)
Q=2*130*(327.5-25=?

Answer 2

Now heat needed to melt the lead
Q=m*latent heat of fusion of lead
Q=2*2.04*10^4=?

Answer 3

Now add those 2 Q to get total heat needed

Answer 4

Response plz!!!!!

Answer 5

78650 + 40800 = 119450 ?

Answer 6

@shamim

Answer 7

@jaysabelle that's right!

Answer 8

@matt101 Thank you!