Question

@phi calculus help!

Answer 1

I would first try to figure out the limits: start and end values of the integral
any ideas ?

Answer 2

0 to 3?

Answer 3

I am looking at the sum
\[\sum_{i=1}^{n} f(a+i \Delta x)\]
where dx is approaching zero.

Answer 4

It seems that the first value we will get is f(a)
if we put in (b-a)/n for dx and evaluate at i=n
the last term
is f( a + n*(b-a)/n)

Answer 5

and that is to find the limit?

Answer 6

I'm thinking that simplifies to b
a+b-a= b
so the start is a and the finish is b

it's a start...

Answer 7

so b is 3?

Answer 8

looking at the actual problem
(2+ i * 3/n) * 3/n
and matching that with the top right expression
I would say f(a+ i Dx) matches with (2 + i*Dx)
and Dx with 3/n

Answer 9

if we call "a+iDx" x (for the moment)
we have f(x) = x
in other words, we have a simply y= x
as the function

now match a with 2 and using the idea that a is the start limit, I would say we start at 2

the Dx is 3/n matches with (b-a)/n
so 3 = b-a
but a is 2, so 3 = b-2
and b= 5
I would say the limits are 2 to 5

Answer 10

ooo just kidding hahaha it would be D

Answer 11

so expect something like
\[ \int_2^5 x \ dx\]

Answer 12

thank you!!! and just asking, the last question of mine that you were on, was right, right??

Answer 13

Yes, I think so.
I went through some substitutions and go the same answer.
Using a table is much faster (if they allow that )

Answer 14

thank you (:!! and yes they do, i have one more problem, will you be able to help me?