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Mathematics 14 Online
OpenStudy (anonymous):

math help!

OpenStudy (anonymous):

OpenStudy (pinklion23):

I'll Help

OpenStudy (anonymous):

good

OpenStudy (pinklion23):

OMG this is a bit confusing

OpenStudy (anonymous):

@mathmath333 @AnswerMyQuestions @iGreen @IrishBoy123

OpenStudy (anonymous):

Geez lu weez!!! What grade you in?

OpenStudy (pinklion23):

yeah may i ask the same thing

OpenStudy (anonymous):

im in 8th grade advance

OpenStudy (anonymous):

Geez Im in seventh and we did this and i failed so sorry i cant help

OpenStudy (mathmath333):

\(\large \color{black}{y=kx.\tag{1}\\~\\ }\) find so first put the value of \(y=10\) and \(x=-3\) and find the value of \(k\)

OpenStudy (anonymous):

would it be C?

OpenStudy (mathmath333):

first find \(k\) then only we can get the answer

OpenStudy (pinklion23):

yeah im in 7th too sorry cant help

OpenStudy (anonymous):

its D > @mathmath333

OpenStudy (mathmath333):

how ?

OpenStudy (anonymous):

isn't it D?

OpenStudy (anonymous):

@AngusV @annipuppi @MeganEdward @inkyvoyd @ilovebmth1234 @inkyvoyd

OpenStudy (mathmath333):

\(\large \color{black}{y=kx.\tag{1}\\~\\ k=\dfrac{y}{x}\\~\\ k=-\dfrac{10}{3}\\~\\ }\) now put the value of \(k\) back in equation \((1.)\) with \(x=-1\)

OpenStudy (anonymous):

so its C?

OpenStudy (mathmath333):

yep

OpenStudy (anonymous):

thanks SIR:)

OpenStudy (mathmath333):

wait lol its \(D.\)

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