What is the theoretical yield of Na2SO4, in grams?
@ryanwhite499 @Hoslos @felipecasal
what do you think it is..?
Hold on I'll be back
Yield, you mean molecular mass?
@Hoslos : The theoretical yield is the amount predicted by a stoichiometric calculation based on the number of moles of all reactants present.
Exactly. I asked that because I feel there is lack of information. At least we should hae had the amount of moles reacted in a reaction or something. The statement looks very vague.
the equation is: H2SO4+2NaOH-> 2H2O+Na2SO4
This is math @boricua5
no, its chemistry
Oh ok. I thought you had to plug the numbers in and stuff
Yes, you deal with numbers @ryanwhite499 , but this is stoichiometry, part of chemistry responsible for calculations.
I know @Hoslos. I'm still trying to figure this out. I thought this was a worded math problem at first.
@boricua5 , I think I need more information, like what amoun reacted, because if you simply give me the reaction, the yield would obviously be 100%, would not be?
Ok.
the limiting reactant is 10.8g of Na2SO4
Ok. Now we are talking. Using your periodic table to find the molecular mass of Na2SO4 is (23*2)+32+(16*4)= 142g. Using ratio of the obtained amount to the expected one is (10.8:142)*100= 7.6%
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