Can anyone tell me why x^2 − 8x − 11 is prime? I know it is prime, I just don't know how to explain why it is.
\[x ^2 - 8 - 11\]
is the trinomial
a number is prime if it can only be divide by 1 and itself, right?
yes
so if one part in the equation is prime the equation itself is prime?
I guess this equation has no whole number factors
or solutions*
im confused now :?
ok what are the solutions of \(x^2-16=0\)
(x+4) (x-4)
you can't factor it like that because you can't write -8 in terms of the factors of 11, you'd have to complete the square
\(x^2 − 8x − 11=(x-4)^2-27\)
Then how do i make x2 − 8x − 11 a prime equation?
its asking to find a prime trinomial and explain why it is prime. I went to another site and the said it was prime so i came here. So i need a new trinomial...
it is prime
http://www.saylor.org/site/wp-content/uploads/2013/02/RWM102-9.3.4-Prime-Trinomials-FINAL.pdf remember what I said about the factors of 11?
yes
only 11 and 1 because it is prime
\(x^2-8x-11\) we want factors of -11 that add/subtract up to -8 Listing the factors of -11: -1 x 11= -11 none (well in this case we only have one) of these add up to -8 so this can't be factored
that makes sense now
thank you (:
anytime c:
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