Question

can someone help me simplify this?

Answer 1

Okay, so you have
\(\Large (\frac{7*5*2}{7*3})^2\times(\frac{5^0}{2^{-3}})^3\large\times2^{-9}\)

Answer 2

First step. Do the \(\large7*5*2\) and the \(\large 7*3\). Can you do that @rubyredgirl20 ?

Answer 3

1st one is 70.. second one is 21

Answer 4

The first section you can just pull the ^2 into all the numbers, and since 7^2 will then be above and below we can take it away. Then we're left with (5^2*2^2 over 3^2) which equals 100 over 9

Answer 5

Good job. So now you have
\(\Large (\frac{70}{21})^2\times(\frac{5^0}{2^{-3}})^3\large\times2^{-9}\)

Now do \(\large 5^0\) and \(\large2^{-3}\)

Answer 6

0 and 0.125

Answer 7

Second part, as anything in the power of zero equals one, we can just change 5^0 to 1

Answer 8

not quite. Remember that any number to the 0 power equals 1.

Answer 9

alright.. 1 and 0.125

Answer 10

Also, i'd leave like this: \(\large 2^{-3}=\Large\frac{1}{2^3}=\frac{1}{8}\)
That way you can change this:
\(\Large(\frac{5^0}{2^{-3}})^3\rightarrow(\frac{1}{\frac{1}{8}})^3\rightarrow (8)^3\)

Answer 11

alright

Answer 12

So now we have
\(\Large (\frac{70}{21})^2\large\times(8)^3\times2^{-9}\)

What is \(\large 8^3\) and \(\large 2^{-9}\)?

Answer 13

512 and 0.001953125

Answer 14

Once again, I'd leave \(\large 2^{-9}\) in fraction form. Can you do that?

Answer 15

idk how i typed this into my calc and it gave me this

Answer 16

When simplifying negative exponents, it is best not to use a calculator until you convert to fraction form.
\(\large 2^{-9}=\Large\frac{1}{2^9}=?\)
What does \(\large 2^9\) equal?

Answer 17

(you can use a calc now)

Answer 18

lol srry i had to do something for my mum just a sec

Answer 19

512