what are the zeros of the related function to this equation x^2-4x-21=0
To factor this you need 2 numbers, whose product is -21 ans whose sum is -4
it factors to (x + a)(x + b) = 0 where a and b are the 2 numbers
so the zeros are -21 and 4 or just 2?
no a and b have to be found first ab = -21 a + b = -4 can you solve this system of equations?
a and b are the 2 numbers welshfella talked about
a+b+-4 -7+3?
right -7*3 = -21 and -7 + 3 = -4
so we have (x - 7)(x + 3) = 0 now it easy to find the zeroes
can you solve that?
you have 2 expressions multiplied together to give zero therefore either one of them must equal zero so we have x - 7 = 0 and x + 3 = 0 solve these 2 equations and you have your answer
x=7 & x=3?
not quite
one of them should be negative
-7?
x + 3 = 0 add -3 to both sides
-3... my bad
x + 3 - 3 = -3 x = ?
yes answer is {-3,7}
- this is called the solution set
im really lost im sorry
which part are you lost on?
the question is what are the ZEROS of the related function im just confused at finding the zeros I guess...
the zeros are the values of x which make the function equal to zero That is why you write x^2 - 4x - 21 = 0. They correspond to the points where the function cuts the x-axis ( where the function = 0)
the graph looks a bit like this |dw:1426627060504:dw|
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