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John’s piggy bank contained 7 dimes and 3 quarters. He pulled out 1 coin without looking. Without replacing the first coin, John then pulled out a second coin. What is the probability that both coins were dimes? Express your answer in simplest form.
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\[\frac{ ? }{ ? }\]
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plz help
the first dime, how many ways can that occur,
7 dimes total or 10 coins total
ok, so the chance to pick a dime will be 7/10, right?
now once you pick a dime, there are 6 dimes left (out of 9 coins). multiply probabilities
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$$ \Large \frac{7}{10}\cdot \frac{6}{9} $$
oh ok so it is\[\frac{ 42 }{ 90 }\]
or\[\frac{ 21 }{ 45 }\]
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