Transform the following polar equation into an equation in rectangular coordinates: r=-4sin(theta)
Don't you use this equation y = r*sin(theta) or is how it is already set up?
Would the answer be C. x^2+(y+2)^2=4
Answer would be C, yes, you are 100% correct :)
hmmm how did you get \(\bf x^2+(y+2)^2=4\) anyway?
= 4sinθ Multiply both sides by r. r² = 4rsinθ x² + y² = 4y x² + y² - 4y = 0 x² + (y² - 4y + 4) = 0 + 4 x² + (y + 2)² = 4
@jdoe0001
yeap... that's exactly correct :)
so is a circle with a radius of 2, centered at (0 , -2)
@jdoe0001 now if the 4 was positive r=4sin(theta) would the answer be x² + (y - 2)² = 4 the difference being (y-2) instead of (y+2)?
Again correct mister :) You rock !
yeap
if the 4 were positive that means as you move it over the left side, it'd turn into a -4y so the middle term of the trinomial is negative, yielding then (y-2)
yep. at that time the r=+4sin(theta)
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