Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (kj4uts):

Transform the following polar equation into an equation in rectangular coordinates: r=-4sin(theta)

OpenStudy (kj4uts):

OpenStudy (kj4uts):

Don't you use this equation y = r*sin(theta) or is how it is already set up?

OpenStudy (kj4uts):

Would the answer be C. x^2+(y+2)^2=4

OpenStudy (anonymous):

Answer would be C, yes, you are 100% correct :)

OpenStudy (jdoe0001):

hmmm how did you get \(\bf x^2+(y+2)^2=4\) anyway?

OpenStudy (kj4uts):

= 4sinθ Multiply both sides by r. r² = 4rsinθ x² + y² = 4y x² + y² - 4y = 0 x² + (y² - 4y + 4) = 0 + 4 x² + (y + 2)² = 4

OpenStudy (kj4uts):

@jdoe0001

OpenStudy (jdoe0001):

yeap... that's exactly correct :)

OpenStudy (jdoe0001):

so is a circle with a radius of 2, centered at (0 , -2)

OpenStudy (kj4uts):

@jdoe0001 now if the 4 was positive r=4sin(theta) would the answer be x² + (y - 2)² = 4 the difference being (y-2) instead of (y+2)?

OpenStudy (anonymous):

Again correct mister :) You rock !

OpenStudy (jdoe0001):

yeap

OpenStudy (jdoe0001):

if the 4 were positive that means as you move it over the left side, it'd turn into a -4y so the middle term of the trinomial is negative, yielding then (y-2)

OpenStudy (anonymous):

yep. at that time the r=+4sin(theta)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!