Determine whether it is a ellipse or hyperbola.
\[8x^2 - 2x = 8y - 3y\]
@pitamar You shall help me lol
is it 8y - 3y on the right? that is just 5y isn't it?
Oops typo it's 8y -3y^2 Wish it was that easy
It actually makes more sense =) it wouldn't be either if it was 5y..
ok, so let's see we have
$$8x^2 - 2x = 8y - 3y^2$$Right?
Yea
Let's move everything to the left. what would that be?
8x^2 -2x - 8y -3y^2 = 0 ?
arm, you have a sign mistake there
Oh plus 3y^2
Yes, so $$8x^2 - 2x + 3y^2 - 8y = 0 $$
Now, in fact I'd say that this is enough for us to tell what it really is..
Ellipse?
Yea so Ellipes I think
in fact I made a mistake I should ahve added factors to x and y.. which would make it uglier. let me fix it sec
Ellipse $$(ax - h)^2 + (by-v)^2 = c^2$$ Hyperbola $$(ax - h)^2 - (by-v)^2 = c^2$$
Now, we can see that in our case no matter what constants we add... we're still left with something like the first.. addition of two squares
So yes ellipse
So pretty much the difference in the to is add and subtract.
yep. addition of squares of subtraction of squares Here is the graph btw: http://www.wolframalpha.com/input/?i=8x%5E2+-+2x+%3D+8y+-+3y%5E2
Thanks man. You haven't failed me yet Lol
or* sure no problem =)
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