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Mathematics 4 Online
OpenStudy (anonymous):

Determine whether it is a ellipse or hyperbola.

OpenStudy (anonymous):

\[8x^2 - 2x = 8y - 3y\]

OpenStudy (anonymous):

@pitamar You shall help me lol

OpenStudy (anonymous):

is it 8y - 3y on the right? that is just 5y isn't it?

OpenStudy (anonymous):

Oops typo it's 8y -3y^2 Wish it was that easy

OpenStudy (anonymous):

It actually makes more sense =) it wouldn't be either if it was 5y..

OpenStudy (anonymous):

ok, so let's see we have

OpenStudy (anonymous):

$$8x^2 - 2x = 8y - 3y^2$$Right?

OpenStudy (anonymous):

Yea

OpenStudy (anonymous):

Let's move everything to the left. what would that be?

OpenStudy (anonymous):

8x^2 -2x - 8y -3y^2 = 0 ?

OpenStudy (anonymous):

arm, you have a sign mistake there

OpenStudy (anonymous):

Oh plus 3y^2

OpenStudy (anonymous):

Yes, so $$8x^2 - 2x + 3y^2 - 8y = 0 $$

OpenStudy (anonymous):

Now, in fact I'd say that this is enough for us to tell what it really is..

OpenStudy (anonymous):

Ellipse?

OpenStudy (anonymous):

Yea so Ellipes I think

OpenStudy (anonymous):

in fact I made a mistake I should ahve added factors to x and y.. which would make it uglier. let me fix it sec

OpenStudy (anonymous):

Ellipse $$(ax - h)^2 + (by-v)^2 = c^2$$ Hyperbola $$(ax - h)^2 - (by-v)^2 = c^2$$

OpenStudy (anonymous):

Now, we can see that in our case no matter what constants we add... we're still left with something like the first.. addition of two squares

OpenStudy (anonymous):

So yes ellipse

OpenStudy (anonymous):

So pretty much the difference in the to is add and subtract.

OpenStudy (anonymous):

yep. addition of squares of subtraction of squares Here is the graph btw: http://www.wolframalpha.com/input/?i=8x%5E2+-+2x+%3D+8y+-+3y%5E2

OpenStudy (anonymous):

Thanks man. You haven't failed me yet Lol

OpenStudy (anonymous):

or* sure no problem =)

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