Question

Help....;) Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is the probability that neither A or B occurs?

0.42
0.10
0.70
0.12

Answer 1

so....whats the answer from the choice?

Answer 2

so, 0.70?

Answer 3

haha yes of course : /

Answer 4

\[\large P(\bar {A})=1-0.3=0.7\]
\[\large P(\bar{B})=1-0.4=0.6\]
\[\large P(\bar{A} \cap \bar{B})=P(\bar{A}) \times P(\bar{B})=0.7\times0.6=you\ can\ calculate\]

Answer 5

you're the real mvp +kropot72
so, it's 0.42

Answer 6

Yes, 0.42 is correct.

Answer 7

The required probability is the intersection of the probabilities of A not occurring and B not occurring.