solving linear systems of equations; addition
-6x=48-6y
-4x=50-6y

Question

solving linear systems of equations; addition
-6x=48-6y
-4x=50-6y

bloomlocke367 · Answer

hey, I can help :)

bloomlocke367 · Answer

does it matter if you use substitution or elimination to solve?

anonymous · Answer

it doesnt say. it just wants to solve for x and y .

bloomlocke367 · Answer

okay... well elimination would be easier..

bloomlocke367 · Answer

do you know how to do that?

anonymous · Answer

no

bloomlocke367 · Answer

actually.. nevermind XD sorry, we'll use substitution..

bloomlocke367 · Answer

pick one equation and decide to solve for either x or y

anonymous · Answer

ugh i guess the first one x

bloomlocke367 · Answer

okay.. so divide both sides by -6

bloomlocke367 · Answer

what do you get?

bloomlocke367 · Answer

Sorry, I have to go to bed, but @TheSmartOne should be able to help you :)

bloomlocke367 · Answer

where'd they go? sorry @TheSmartOne

thesmartone · Answer

It's okay. I'll put out the steps for them for when they return :)

bloomlocke367 · Answer

okay

thesmartone · Answer

First of all, Welcome to OpenStudy!! @rhondahyde16

To solve your question, it would be easy to solve by elimination.

So if we subtract your two equations as it is, it will look like this:

$\sf ~~~-6x=48-6y\-\
~~~-4x=50-6y\---------$

If we subtract that, we should be able to eliminate 6y.

And to complete that what is $\sf -6x-(-4x)=?$

And what is $\sf 48-50=?$

And set them equal to each other like

$\sf -6x-(-4x)=48-50$

And solve for x.

Once you get x, plug in the value of x into any equation and solve for y. And you answer will be (x,y)