Question

IS THIS CORRECT?

Answer 1

@Saisuke<3 @TheSmartOne @dan815

Answer 2

I got 983.85 not 983.84

Answer 3

A really small difference but yea..

Answer 4

i put 983.34

Answer 5

@TheSmartOne

Answer 6

Oh my. I'm seeing stuff now lol

Answer 7

Whats right???

Answer 8

O.o i got 173.38392

Answer 9

OH VOLUME

Answer 10

.......im so smart. i did ALLLL THAT WORK FOR. like. a lot of nothing.

Answer 11

ehhh.i know right

Answer 12

i got \[313.168 \pi~inch^3\]

Answer 13

http://openstudy.com/study#/updates/550736c5e4b03b61148992be

Answer 14

So lets see the formula is

\(\sf V= \pi\times r^2\times h\)

\(\sf V= \pi\times 9.3^2\times 3.7\)


\(\sf V= \pi\times 86.49\times 3.7\)


\(\sf V= \pi\times 320.013\)

\(\sf V= 1005.35048985\)

Answer 15

OOOOOOOOOO.O

Answer 16

it is 9.2 not 9.3

Answer 17

THIS IS SO COMPLICATED

Answer 18

Yaa

Answer 19

so 1005.35

Answer 20

T-T no one is helping me on mai question

Answer 21

This is interesting O.o

Answer 22

what is it in like simplified form?

Answer 23

O.o

Answer 24

And then this: http://prntscr.com/6i5kpq

Answer 25

is that correct?

Answer 26

idk... this is getting interesting...

@sleepyhead314 @sleepyjess @acxbox22

Answer 27

lol
give me a minute to do it :)

Answer 28

k thanks @sleepyjess !!!

Answer 29

Ok, do you know the formula for the volume of a cylinder?

Answer 30

I know what you and @TheSmartOne were doing wrong :)

Answer 31

I knew I should have tagged Jess :P

Answer 32

They want you to leave it in terms of \(\pi\)

Answer 33

ok

Answer 34

\(\color{blue}{\text{Originally Posted by}}\) @sleepyjess
They want you to leave it in terms of \(\pi\)
\(\color{blue}{\text{End of Quote}}\)

What @MARC_ messaged me about. Aha lol

Answer 35

So pretty much, do exactly what you did before, but don't multiply by 3.14

Answer 36

ok

Answer 37

313.168

Answer 38

Yes!

Answer 39

what net?

Answer 40

That's it!

Answer 41

are u sure??

Answer 42

oh i see

Answer 43

Yes, I'm sure :)

Answer 44

can you check 1 more?

Answer 45

Sure :) Just open a new question and tag me