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A 3.00kg box slides down a rough incline plane from a height h of 1.63m. The box had a speed of 2.33m/s at the top and a speed of 1.90m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.).
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You can solve this using conservation of energy. I'll call mechanical energy (ME), gravitational potential energy PE, kinetic energy KE, and heat lost due to friction H. Initial conditions represented by (i) and final conditions represented by (f): \[ME_i=ME_f+H\]\[PE_i+KE_1=PE_f+KE_f+H\]\[mgh_i+{1 \over 2}mv_i^2=mgh_f+{1 \over 2}mv_f^2+H\] If you plug in the appropriate numbers from the question into this equation and solve for H, you'll have your answer!
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