Question

2.

Above are two different models of the same triangle. If the area of the model on the left is 24 sq cm, what is the area of the model on the right?
96 sq cm
120 sq cm
48 sq cm
26.5 sq cm

Answer 1

26.5

Answer 2

I don't even see a model.

Answer 3

https://app138.studyisland.com/pics/252368num5.png

Answer 4

dont need a modle to no that

Answer 5

then what do u think william.1233

Answer 6

if u dont need a model

Answer 7

How are you going to say you don't need a model when it clearly states it in the problem?

Answer 8

so D is the answer

Answer 9

yes it is d

Answer 10

Can you explain why it is D?

Answer 11

u can get help from it http://openstudy.com/study#/updates/54e8d0bce4b08080d2e57891

Answer 12

k

Answer 13

it's not D.

Answer 14

k so wat is it

Answer 15

Have you tried solving it?

Answer 16

Think of the units for area.

Answer 17

i think it is 48

Answer 18

Hope you're not just guessing.

Answer 19

no

Answer 20

she ant guessin how we no u ant guessing

Answer 21

Fir the triangle on the left, you're given

1 cm = 5 ft. \(\therefore\)

1 cm\(^2\) = 25 ft\(^2\)

Area for the first triangle = 24 cm\(^2\) \(\implies \triangle_1=600~ft^2\)

Answer 22

k thanx

Answer 23

And so the second ratio would be

1 cm = 2.5 ft

1 cm\(^2\) = 6.25 ft\(^2\)

\[A_{\triangle2} = \frac{600~}{6.25~} = 96~cm^2\]

Answer 24

Try to work out the problem next time instead of blatantly choosing answers.

Answer 25

ho u talking to

Answer 26

I'd still like to know how you went about getting 26.5 @william.1233 . Could you explain the process?