Question

What is the area of the figure?



A.
84 in2

B.
189 in2

C.
231 in2

D.
315 in2http://static.k12.com/calms_media/media/1567000_1567500/1567392/1/7b1872398d0c0757036a9d22d691b40932560e0d/MS_IMB-1401012-1100711.jpg

Answer 1

@sammixboo @AnswerMyQuestions

Answer 2

Pls help

Answer 3

@Data_LG2

Answer 4

The area of a trapezoid with bases \(b_1\) and \(b_2\) and height \(h\) is
\[A=\frac{1}{2}(b_1+b_2)h\]
Here we have two trapezoids conjoined by a common base, with heights \(x_1\) (on the left) and \(x_2\) (on the right).

The area is then
\[A=\underbrace{\frac{1}{2}(9+13)x_1}_{\text{left}}+\underbrace{\frac{1}{2}(13+9)x_2}_{\text{right}}=\frac{1}{2}(9+13)(x_1+x_2)\]
You're given that \(x_1+x_2=21\), so
\[A=\frac{1}{2}(22)(21)=\cdots\]