Quadrilateral ABCD is located at A (−2, 2), B (−2, 4), C (2, 4), and D (2, 2). The quadrilateral is then transformed using the rule (x−3, y+4) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.
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OpenStudy (anonymous):
A'= -5,5
B'= 1,8
C'= -1,8
D'= -1,6
OpenStudy (anonymous):
i need help with the last part
OpenStudy (anonymous):
@e.mccormick
OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
can you help
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OpenStudy (campbell_st):
I think you need to check you points A', B', C' and D'
OpenStudy (campbell_st):
my advice would be then to plot the 2 quadrilaterals...
then join the corresponding vertices and see what happens
OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
how are A', B', C' and D' wrong
OpenStudy (campbell_st):
here is an image...
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OpenStudy (campbell_st):
A = (-2, 4) rule (x -3, y + 4) A'(-2 -3, 2 + 4) = A'(-5, 6)
OpenStudy (campbell_st):
so check you points
OpenStudy (anonymous):
Isent a -2,2
OpenStudy (anonymous):
so -5,6 would be b right
OpenStudy (anonymous):
a=-5,6
b=-5,8
c=-1,8
d=-1,6
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OpenStudy (anonymous):
right
OpenStudy (campbell_st):
now what happens if you join the corresponding vertices
OpenStudy (anonymous):
thats where im stuck
OpenStudy (campbell_st):
well I think you get a prism... so which type of prism..?
OpenStudy (anonymous):
Irregular prism
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