i anyone need help post questions here
Sue counted the turtles and birds in the pond. She counted 14 heads and 44 legs. How many turtles did Sue count? A. 4 B. 8 C. 11 D. 22
i would say 11
whats 9+10=?
i think is 21
it is 21
ok just making sure
i saw a video of someone doing it
@Jakob_ambrose
it is 11 the answer to ur question
medal if helped
how do i medal
click best response @Jakob_ambrose
the population of a local species of dragonfly can be found using an infinite geometric series where a1 = 42 and the common ratio is 3/4. write the sum in sigma notation and calculate the sum that will be the upper limit of this population
simplifi it
lol idk how
ok well let me get somweone to help me and you
@iGreen
the answer can not be 11 unless there were no birds lol
what
the original questions says she counted BIRDS and TURTLES 14 heads, 44 legs only way you can get 11 turtles would be if there were 0 birds but then there wouldn't be 14 heads
unless some turtles had an extra head lmao
mutant tutles
oh ok srry
you would make simultaneous equations you know there are 14 heads in total you know a bird and a turtle each have 1 head so if we let turtles be x and birds be y so you get an equation of x+y=14 then you know there are 44 legs you know a turtle has 4 legs, and bird has 2 legs so you get another equation of 4x+2y=44 now solve simultaneously
for the geometric question
ur already right because there is 14 heads
you know the sum to infinity of geometric series is \[\frac{ a }{ 1-r }\] where a is the first term and r is the ratio
have a go at solving both questions from what I have told you and let me know if you still need help
@phi
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