Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
4/3
OpenStudy (anonymous):
yea 4/3
OpenStudy (hulkart):
Find the value of the trigonometric function sin (t) if sec t=-4/3 and the terminal side of angle t lies in quadrant II.
OpenStudy (anonymous):
Later guys..gtg..bye
OpenStudy (anonymous):
Later guys..gtg..bye
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[+\sqrt{6}/4\] as it is in quardrant 2
OpenStudy (hulkart):
It's -4....check again
OpenStudy (hulkart):
i said minus4/3
OpenStudy (anonymous):
I didnt understand, b specific if you are trying to tel me
OpenStudy (hulkart):
ok I got that one...
For this special angle, draw the angle and find the reference angle: t=2pi/3
pi/3
pi/6
2pi/3
pi/3
*the diagram shows a circle divided into four and arrow pointing northwest, southwest, northeast and northwest....
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
pi/3 is answer.
OpenStudy (hulkart):
For the function given, state the starting point for a sample period:
f(t)=-cos[2t-pi/4]+1