What is the slope-intercept form of the function that contains the point (3, 4) and has a slope of 2?
y = x +
Will fan/medal
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OpenStudy (anonymous):
@mathstudent55
@paki
@iambatman
OpenStudy (ahsome):
First of all, the basic equation of a linear equation is:
\[\huge{y=mx+c}\]
Where:
\[m=Slope\]\[c=y-intercept\]
OpenStudy (ahsome):
The problem is that we don't know what \(c\) is. So we need to find it
Another form of expressing a linear equation is:
\[\huge{y-y_1=m(x-x_1)}\]
Where:
\[m=Slope\]\[Point=(x_1,y_2)\]
OpenStudy (anonymous):
\[y-4=m(x-3)?\]
OpenStudy (ahsome):
Exactly. But we know what \(m\) is, right?
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OpenStudy (anonymous):
No
OpenStudy (ahsome):
Yes we do. What is the slope?
OpenStudy (anonymous):
Oops 2..
OpenStudy (ahsome):
Its fine :)
Now, we know a point, and we know the slope, so lets work from there!
\[y-y_1=m(x-x_1)\]\[y-4=2(x-3)\]\[y-4=2x-6\]\[y=2x+2\]
OpenStudy (ahsome):
Sorry, its \(-2\)
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OpenStudy (anonymous):
hmm...
\[\frac{ y }{ y }=2x+\frac{ 2 }{ y }\]
OpenStudy (ahsome):
Why do you wan't to divide by y?
OpenStudy (anonymous):
Isn't that how it works?
OpenStudy (ahsome):
Nope. You don't need to divide by y :)
OpenStudy (anonymous):
Ugh.
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