the diagonals oy a parallelogram PQRS are along the lines x+3y=4 and 6x-2y=7 then PQRS must be a ?
*of
@rational please help
@ikram002p may u please help me
Hint : the given lines are perpendicular
i know that
Next use this : A parallelogram with perpendicular diagonals is called a "rhombus"
oh so its not square?
@rational
it has to be a rhombus i think..
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hmm
yeah it can be square as well
it has to be a rhombus
ikky took a ruler to her screen to draw out those lines :P Hahaha jk!
so which is right
jhanny lol xD
not all rhombuses are squares so saying "it has to be a square" is incorrect
i said it might be also square xD
it can be a cube also if you stretch it and take it to 3D (some sarcasm)
:P
lol this souns interesting @rational
this is why the one who ask should be careful :P any imagination answer can be correct
nope, the only possible answer is "rhombus"
but yeah according to the definition of rhombus its the parallelogram of perpendicular diagonals, and square belongs to rhombus family so hmmm
well the ans is rhombus but i just need a proof for that :)
consider a quadratic equation ax^2 + bx + c = 0 and it is given that b^2-4ac > 0 what can you say about the nature of roots ?
oh @rvc all u need is to find the slope of both lines to show they are perpendicular :)
options : 1) roots must be integers 2) roots must be rationsl 3) roots must be perfect squares 4) roots must be mangoes
okay then
1)
the answer is actually NONE OF THEM.
because `b^2-4ac > 0` is only a sufficient condition for "real roots"
ohh yes
hahaha ok got it xDDDDDDD if there is other options like they might be integer they might be rational they might be morons any thing fits :P
ugh, the point im trying is to convince us that none of them fit
i know, i totally agree when the student still in school i just wanna see what @rvc is about to say
OK \[b^2 - 4ac \ge 0\implies \text{roots are real}\] end of story.
\[b^2 - 4ac \ge 0\implies \text{roots are integers}\] is incorrect as it doesn't hold always.
rectangle,rhombus,square,cyclic quadrilateral
\[\text{Sheela's dress became wet} \implies \text{It rained}\] the implication is wrong because there might be other reasons for Sheela to become wet
sheela is my math teacher's name lol
\[\text{perpendicular diagonals} \implies \text{parallelogram is square}\] the implication is wrong because there might be other possibilities for parallelogram other than square.
xD then dont tell her husbend were using her in question @rvc xD
However below implication holds \[\text{perpendicular diagonals} \implies \text{parallelogram is rhombus}\]
ok i agree
lol @ikram002p
well im not convinced its a rhombus
what u are thinking it is ?
im confused
you may google for a proof of "A parallelogram with perpendicular diagonals is a rhombus"
ok so ur agree both lines are perpendicular diagonals ?
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