Question

16/(x+2) - 3 = (1/3)(q+1)

Answer 1

What's the question?

Answer 2

simplify and find x

Answer 3

Is that "q" another variable?

Answer 4

oh no its supposed to be an x

Answer 5

\[\frac{16}{x+2} - 3= \frac{1}{3}(x+1)\]

Answer 6

First simplify the RHS of the equation

Answer 7

i keep getting different answers

Answer 8

What do you get on the RHS when you distribute \(\frac{1}{3}\)?

Answer 9

1/3x^2+x2-13?

Answer 10

well 1/3 x^2 + x - 12.3

Answer 11

Not quite, i asked just for the RHS :P

Breaking this up into steps and then simplifying.

RHS I got \(\frac{1}{3}x+\frac{1}{3}\)

Answer 12

yes same

Answer 13

So our equation becomes \[\frac{16}{x+2}-3=\frac{1}{3}x+\frac{1}{3}\]
Now we want to add \(+3\) to both sides of the equation. What does your equation become?

Answer 14

16/x+2= 1/3x + 10/3

Answer 15

Awesome. I got the same.

Answer 16

Now rewrite it so you've got \[\frac{16}{x+2}=\frac{x}{3}+\frac{10}{3}\]Notice how the two fractions on the RHS have a common denominator of 3? That means we can combine them as one fraction.

Answer 17

So we will have \[\frac{16}{x+2}=\frac{x+10}{3}\]

Answer 18

Now what do you get when you cross multiply these two fractions?

Answer 19

\[48 = (x+2)(x+10)\]

Answer 20

\[48 = x ^{2} + 12x + 20\]

Answer 21

That becomes \[x^2+12x-28 =0\]Just factor this.