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Chemistry 18 Online
OpenStudy (anonymous):

what is the percent ionization in a 0.15 M solution of HF?

OpenStudy (anonymous):

HF is a weak monoprotic acid, \[\color{green}{K_a = 6.6 \times 10^{-4} \qquad \text{@ STAP}}\] Write the equation for the partial dissociation of this acid and apply the equilibrium law expression. Fronm there, I hope you should be able to work out the answer.

OpenStudy (anonymous):

(Set up an ICE chart. It will help.)

OpenStudy (anonymous):

I got my value from a different source (Lange's Handbook of Chemistry, 13th edition). Use the value from your source if you want. It will not make that much of a difference.

OpenStudy (anonymous):

thank you!

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