Question

if one of the line represented by the equation ax^2+2hxy+by^2=0 is coincident with one of the line represented by a'x^2+2h'xy+b'y^2=0 then

Answer 1

same partial derivatives..

Answer 2

@SolomonZelman here it is

Answer 3

these equations look like quadratics, but if you want to get a line, they will need to be perfect squares

Answer 4

(ab'-a'b)^2=4(ah'-a'h)(hb'-h'b)
(ab'+a'b)^2=4(ah'-a'h)(hb'-h'b)
(ab'-a'b)^2=(ah'-a'h)(hb'-h'b)
(a'b'-ab)^2=(ah-a'h')(hb-h'b')
these are the options

Answer 5

@rational @Jhannybean @hartnn @perl help

Answer 6

@TheSmartOne @Kainui @iambatman help me please

Answer 7

@dan815

Answer 8

@sammixboo

Answer 9

Ah sorry can't help ;-;

Answer 10

@perl @SolomonZelman

Answer 11

It's 0046, local time.
Have to bail out now.
Sorry.

Answer 12

@ParthKohli @StudyGurl14 @EclipsedStar @rational

Answer 13

@dan815 may u help

Answer 14

did you make it with a script ? XD

Answer 15

: )

Answer 16

send me the script

Answer 17

mouse listener or whatever..

Answer 18

hmmm

Answer 19

@satellite73 im sure you can help me

Answer 20

@satellite73 need help

Answer 21

@uri

Answer 22

@Vincent-Lyon.Fr

Answer 23

@divu.mkr

Answer 24

@bibby @King.Void.

Answer 25

@ikram002p @ganeshie8

Answer 26

@campbell_st @Callisto

Answer 27

@Somy have a look :)

Answer 28

partial derivate will give you two lines...out of four lines a pair will be useless
rest two will be useful. solve them as system of linear equations using cramer rule
you could get the idea by checking the options..they simply suggest of cramer rule

Answer 29

ha
can u solve this question pls @divu.mkr

Answer 30

@YanaSidlinskiy

Answer 31

@ikram002p plssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Answer 32

@ashwinram

Answer 33

hmm

Answer 34

if one of the line represented by the equation ax^2+2hxy+by^2=0 is coincident with one of the line represented by a'x^2+2h'xy+b'y^2=0 then

Answer 35

sharing lines

Answer 36

no the options are mentioned

Answer 37

that is the definition of coincidence

Answer 38

lines on top of each other

Answer 39

\[(y+m_1x)(y+m_2x) = 0\tag{1}\]

\[(y+m_1x)(y+m_3x) = 0\tag{2}\]

Answer 40

if its a perfect square u can get a y=mx relationship

Answer 41

hey wait

Answer 42

im posting this question again in another section

Answer 43

closing this question

Answer 44

we can always break ax^2+bxy+by^2 = 0 as (y+m1x)(y+m2x) = 0

as they represent a pair of straight lines passing through origin