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OpenStudy (agl202):
Hum...
OpenStudy (anonymous):
Wheres the question?
OpenStudy (anonymous):
like tf
OpenStudy (anonymous):
XD
OpenStudy (anonymous):
@everyone please help
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OpenStudy (anonymous):
@perl
OpenStudy (perl):
i might need an abstract algebra book
OpenStudy (perl):
we know that
$$ \Large \log x + \log y = \log ( x * y )$$
OpenStudy (perl):
A function \( \bf f: G \to H \) from a group G to a group H is a homomorphism (or a group map) if \( \bf f(ab) = f(a)f(b)\) for all \( \bf a, b \in G \).
OpenStudy (perl):
actually the only way to make this work would be to define g(x) = e^x , thats why im confused
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OpenStudy (perl):
exp(x + y) = exp(x) * exp(y)
OpenStudy (perl):
exp(x) means \( \bf e^x \)
OpenStudy (anonymous):
@perl
OpenStudy (anonymous):
@perl please number 2,6,8
OpenStudy (anonymous):
@perl
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OpenStudy (anonymous):
@perl
OpenStudy (anonymous):
@perl
OpenStudy (perl):
i dont understand how these questions are entered
OpenStudy (anonymous):
you have the file
OpenStudy (perl):
you want the kernel of e^x ?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
is it 0 or 1 or e
OpenStudy (perl):
The kernel of a group homomorphism is the set of all elements of which are mapped to the identity element of
OpenStudy (anonymous):
so what is the element then?
OpenStudy (perl):
kernel is {0}
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OpenStudy (perl):
because e^0 = 1
OpenStudy (anonymous):
what about number 5
OpenStudy (anonymous):
i guess A
OpenStudy (anonymous):
and al so , A bijective homomorphism is called
endomorphism
Exomorphism
Isomorphism
Automorphism
OpenStudy (anonymous):
is it D
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